\documentclass[12pt]{article}
\usepackage{amsmath}

% Somewhat wider and taller page than in art12.sty
\topmargin -0.4in  \headsep 0.0in  \textheight 9.0in
\oddsidemargin 0.25in  \evensidemargin 0.25in  \textwidth 6.5in

\footnotesep 14pt
\floatsep 28pt plus 2pt minus 4pt      % Nominal is double what is in art12.sty
\textfloatsep 40pt plus 2pt minus 4pt
\intextsep 28pt plus 4pt minus 4pt

\begin{document}

\newcommand{\half}{\frac{1}{2}}
%\newcommand{\be}{\begin{equation}}
%\newcommand{\ee}{\end{equation}}
\newcommand{\be}{\begin{displaymath}}
\newcommand{\ee}{\end{displaymath}}
\newcommand{\bea}{\begin{eqnarray}}
\newcommand{\eea}{\end{eqnarray}}
\newcommand{\bdm}{\begin{displaymath}}
\newcommand{\edm}{\end{displaymath}}
\newcommand{\<}{\langle}
\renewcommand{\>}{\rangle}
\newcommand{\Tr}{\mbox{Tr}}

\centerline{\bf \Large Chroma Euclidean Gamma Matrix Conventions}
\vskip 5mm

For particles of spin-1 can {\em arbitrarily } define a sign convention:
\begin{align}
  \rho(k) &\equiv \bar{\psi} \gamma_k \psi \nonumber \\
  \varrho(k) &\equiv \bar{\psi} \gamma_k \gamma_4 \psi \nonumber\\
  a_1(k) &\equiv \bar{\psi} \gamma_k \gamma_5 \psi \nonumber\\
  b_1(k) &\equiv \bar{\psi}\tfrac{1}{2}  \epsilon_{ijk} \gamma_i \gamma_j \psi \nonumber
\end{align}
With this convention some of the chroma gamma matrices carry a minus sign when creating a state.\\

\vspace{1cm}

\begin{tabular}{c|c|c|c| r| c}
$n_\Gamma(\mathrm{dec})$ & $n_\Gamma(\mathrm{bin})$ & name & $\Gamma$ & state & $\widetilde{n_\Gamma}(\mathrm{dec})$\\
\hline
0 & 0000 & a0 & $1$ & $a_0$ & 15\\
1 & 0001 & rho\_x & $\gamma_1$ & $\rho(x)$ & 14\\
2 & 0010 & rho\_y & $\gamma_2$ & $\rho(y)$ & 13\\
3 & 0011 & b1\_z & $\gamma_1 \gamma_2$ & $b_1(z)$ & 12\\
4 & 0100 & rho\_z & $\gamma_3$ & $\rho(z)$ & 11\\
5 & 0101 & b1\_y & $\gamma_1 \gamma_3$ & $- b_1(y)$ & 10\\
6 & 0110 & b1\_x & $\gamma_2 \gamma_3$ & $b_1(x)$ & 9\\
7 & 0111 & pion\_2 & $\gamma_1 \gamma_2 \gamma_3 = \gamma_5 \gamma_4$ & $\pi$& 8 \\
8 & 1000 & b0 & $\gamma_4$ & $b_0$ & 7 \\
9 & 1001 & rho\_x\_2 & $\gamma_1 \gamma_4$ & $\varrho(x)$ & 6\\
10 & 1010 & rho\_y\_2 & $\gamma_2 \gamma_4$ & $\varrho(y)$ & 5\\
11 & 1011 & a1\_z & $\gamma_1 \gamma_2 \gamma_4 = \gamma_3 \gamma_5$ & $a_1(z)$ & 4\\
12 & 1100 & rho\_z\_2 & $\gamma_3 \gamma_4$ &  $\varrho(z)$ & 3\\
13 & 1101 & a1\_y & $\gamma_1 \gamma_3 \gamma_4 = - \gamma_2 
\gamma_5$ & $- a_1(y)$ & 2\\
14 & 1110 & a1\_x & $\gamma_2 \gamma_3 \gamma_4 = \gamma_1 \gamma_5$ & $a_1(x)$ & 1\\
15 & 1111 & pion & $\gamma_1 \gamma_2 \gamma_3 \gamma_4 = \gamma_5$ &  $\pi$ & 0 \\

\end{tabular}


\end{document}
